When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + λ ). The elastic potential energy stored in the extended wire is:
A
MgL
B
Mg λ
C
MgL
D
Mg λ
Text Solution
Verified by ExpertsThe correct answer is:
D
Strain = 
, stress = 
Energy = 
× stress × strain × volume
= 
× 
× 
× A × L
= 
Mg λ
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